Skip to main content
Have a personal or library account? Click to login
On a generalization of the Cahn-Hilliard type equation with logarithmic nonlinearities in island formation Cover

On a generalization of the Cahn-Hilliard type equation with logarithmic nonlinearities in island formation

Open Access
|Jun 2024

Full Article

1. Introduction

The significance of the Cahn-Hilliard equation in material science cannot be overstated. This equation effectively captures the crucial qualitative aspects of two-phase systems, particularly in relation to phase separation processes. In the realm of material science, the resulting pattern formation is termed as the microstructure of the material, wielding a substantial influence on diverse material properties such as strength, hardness, and conductivity.

The broad applicability of the Cahn-Hilliard model across various evolutionary stages underscores its versatility. It serves as a robust model for early-stage systems, offering a qualitative description for intermediate times, and continues to be relevant for late-stage systems. Notably, the gradual evolution during late stages often occurs at such a slow pace that pattern formation essentially becomes frozen over the relevant time scales. Consequently, the observed practical behavior reflects the long-term dynamics of the system. For a more in-depth exploration, interested readers are directed to references such as [1,2,3,4,5].

Beyond its fundamental role in material science, the Cahn-Hilliard equation finds an application in modeling a diverse array of phenomena. This extends to areas such as population dynamics [6], bacterial films [7], thin films [8, 9], image processing [10, 11], and even celestial phenomena like the rings of Saturn [12].

In a related study [13], the authors explored a model put forth in [14]:

(1)
ςt+Δ2ςΔf(ς)+η(ς)=0,
where
(2)
η(s)=s(s1)
and
(3)
f(s)=(s12)3(s12).
Furthermore, in [15] the author has analysed the model (1) with a regular nonlinear term (3), but with a general source term, which is given by
(4)
η(s)=αs2+βs+γ,
where α > 0 and β, γ ∈ ℝ. The authors in [13, 15] have proved that the solutions can blow up in finite time and exist globally under strong assumptions on the solutions and not only on the initial data. However, the author in [16] considered the model (1)(2) but with logarithmic nonlinear terms f and proved the existence of a solution to the problem.

The Cahn-Hilliard equation incorporating a mass source term is expressed as

(5)
ςt+Δ2ςΔf(ς)+η(x,ς)=0,
where η represents the mass source term. This equation serves as a versatile model with applications in diverse biological contexts, notably in the growth of cancerous tumor and other biological entities. The choice of η determines specific behaviors, for instance, a linear function η(x, s) = αs, α > 0 yields the Cahn-Hilliard-Oono equation, capturing long-range interactions in phase separation (see [17]; see also [18] for the study of the limit dynamics when α approaches zero). A quadratic function η(x, s) = αs(s − 1), α > 0 finds applications in biology [19,20,21,22], particularly in wound healing and tumor growth. Another relevant function, commonly employed in tumor growth scenarios, is η(x,s)=α2(s+1)β(1s)2(1+s)2+s(x,t) , where α and β denote growth and death coefficients. Additionally, the function η(x, ς) = 1Ω\D(x)ς is associated with image inpainting applications, as documented in [23,24,25,26,27], and further explored with non-regular non-linear terms in [28].

In this paper, we explore the model (1) incorporating the nonlinear function η

(6)
η(s)=s2p(1s)
along with a logarithmic nonlinear term. The model is subject to Neumann boundary conditions. Under certain assumptions, we establish the existence of solutions for the problem. It is noteworthy that, as detailed in the article, the solutions in certain scenarios may experience a finite-time blow-up.

2. Mathematical problem

Let Ω ⊂ ℝn, n = 1, 2 or 3 be a bounded and regular domain with boundary Γ. We consider the following problem

(7)
tς+Δ2ςΔf(ς)+η(ς)=0,
(8)
νς=νΔς=0,onΓ,
(9)
ς(0,x)=ς0(x),inΩ.
Assume that all constants are equal to one, ν is the outer unit normal vector to Γ, f = F′ as defined below and η(s) = s2p(1 − s) where p is a strictly positive real number.

Note that

(10)
fλ1.
Let us write F(s)=λ121s2+F1(s) with f1=F1 and introduce for N ∈ ℕ the approximated function F1,NC4(ℝ), which is defined by:
(11)
F1,N(4)(s)=F1(4)11N;ifs11N,F1(4)(s);if|s|11N,F(4)1+1N;ifs1+1N.
(12)
F1,N(k)(0)=F1(k)(0),k=0,1,2,3
and f1(s)=f(s)+λ1s=λ22ln1+s1s

Hence,

(13)
F1,N(s)=1k!F1(k)11Ns1+1Nk;ifs11N,F1(s);if|s|11N,k=041k!F1(k)1+1Ns+11Nk;ifs1+1N.
Setting
FN(s)=λ12(1s2)+F1,N(s),f1,N=F1,N
and
fN=FN,
there holds
(14)
f1,N0,fNλ1,
(15)
FNc1,c10,
(16)
fN(s).sc2FN(s)+|f1,N(s)|c3,c2>0,c30,s,
and
(17)
fN(s+m)fN(m)sc4s4+m2s2c5,c4>0,c50,ands,m.
The constants ci, i = 1, ⋯ , 5 are independent of N for N large enough. More generally,
(18)
fNs+msc6,mFN(s+m)+|f1,N(s+m)|c7,m,s,m(1,1),
where the constants c6,m and c7,m are independent of N for sufficiently large N and exhibit continuous and bounded dependence on m.

Finally, we arrive at

Lemma 1

(19)
|η(s+m)η(m)|c8s2+|ms|+c9
and
(20)
|η(s+m)η(m)|2c10s4+s2(m2+1)+c11.

Proof

|η(s+m)η(m)|=|s2+2sm+ps|s2+2|ms|+p|s|s2+2|ms|+p22+s22c8s2+|ms|+c9
and
|η(s+m)η(m)|2cs2+|ms|+c2cs2+|ms|+12cs4+2s2|ms|+m2s2+2s2+2|ms|+1cs4+2s2m22+s22+m2s2+2s2+212+m2s22+1c10s4+m2s2+s2+c11.
We now introduce the approximated problem
(21)
tςN+Δ2ςNΔfN(ςN)+η(ςN)=0,
(22)
νςN=νΔςN=0,onΓ,
(23)
ςN(0,x)=ς0(x),inΩ.
From (17) and (19)(20) it follows that we have the existence and uniqueness (depending on the regularity of ς0) of the (at least) local in time solution ςN of (21)(23).

2.1. Notations

We denote by (.) the usual L2-scalar product with associated norm ||.||. We also set ||.||−1 = ||(−Δ)−1||, where (−Δ)−1 denotes the inverse of the minus Laplace operator associated with Neumann boundary conditions and acting on zero-mean functions.

More generally, we denote by ||.||X the norm on the Banach space X.

We set .=1Vol(Ω)Ω.dx , being understood that if ζ ∈ H1(Ω) = H1(Ω)′ then

ζ=1Vol(Ω)ζ,1H1(Ω),H1(Ω).
We also set, whenever this makes sense
ζ¯=ζζ.
We note that:
ζ||ζ¯||12+ζ212,ζ||ζ¯||2+ζ212,ζ||ζ||2+ζ212,ζ||Δζ||2+ζ212
are all norms on H−1(Ω), L2(Ω), H1(Ω) or H2(Ω) that are equivalent to the usual norms on these spaces. Furthermore, ||.||−1 is a norm on {ζ ∈ H−1(Ω),〈ζ〉 = 0} which is equivalent to the usual H−1 norm.

Note that the same letter c (and sometimes also c′ or c″) in this paper stands for (generally positive) constants that are independent of N and may change from line to line. The same applies to constants such as cδ, cδ and cδ which depend on a parameter δ.

3. Applications

In this part, we observe the existence and blow up properties of the results founded by using projected scheme.

3.1. Existence and blow up solutions

In this section, our objective is to establish estimates for uN that are independent of N. These estimates can be rigorously justified based on the approximated problems. A crucial aspect involves obtaining a uniform (with respect to N) estimate for fN (ςN) in L2(Ω × (0, T)), where T > 0 is independent of N. This is essential for passing to the limit in the nonlinear term and obtaining a solution to the singular initial problem. Notably, achieving this goal necessitates a uniform (with respect to N) strict separation property for 〈ςN〉 from the singular points −1 and 1. It is worth mentioning that such a strict separation property is straightforward for the original Cahn-Hilliard equation, given the conservation of the spatial average of the order parameter, provided that the same property holds for the initial datum.

We assume that ς0H1(Ω) ∩ L(Ω), with |ς0(x)| < 1 almost everywhere in Ω, and

(24)
|ς0|12δ,δ(0,12],
given. If we first integrate (21) over Ω, we find due to (22),
(25)
dςNdt+η(ςN)=0.
In fact, we have that
dςNdt+Δ2ςNΔfN(ςN)+η(ςN)=0.
Noting that
ΩΔ2ςdx=ΩΔς.1dx+ΓΔςν.ςds=0.
Furthermore,
ΩΔfN(ςN)dx=ΩfN(ςN).1dx+ΓfN(ςN)ν1ds=0,
hence
ddtΩςNdx+Ωη(ςN)dx=0,
which yields
dςNdt+η(ςN)=0.
On the other hand, setting ςN = 〈ςN〉 + ζN, (ζN) = 0 yields
dςNdt+ςN2p(1ςN)=0
and
dςNdt+ςN+ζN2p1ςN=0.
Therefore,
dςNdt+ςN2+2ςNζN+ζN2p1ςN=0,
so that
dςNdt+ςN2+2ςNζN+ζN2p1ςN=0,
it then follows
dςNdt+ςN2p1ςN=ζN2.
Hence, we get
(26)
dςNdt+ηςN=ζN2.
Furthermore, ζN is a solution to:
(27)
tζN+Δ2ζNΔfN(ςN)+η(ςN)¯=0,
(28)
νζN=νΔζN=0,onΓ,
(29)
ζN|t=0=ζ0(x),inΩ.
Since (21) gives,
ζN+ςNt+Δ2ςNΔfN(ςN)+η(ςN)=0ζNt+ςNt+Δ2ςNΔfN(ςN)+η(ςN)=0ζNtg(ςN)+Δ2ζNΔfN(ςN)+η(ςN)=0ζNt+Δ2ζNΔfN(ςN)+η(ςN)¯=0.
ςNν=ζNνandΔςnν=Δζnν.
These equations can be written equivalently, if we multiply by −(Δ)−1, as:
(30)
(Δ)1tζNΔζN+fN(ςN)¯+(Δ)1η(ςN)¯=0,inΩ×(0,T),
(31)
νζN=0,onΓ,
(32)
ζN|t=0=ζ0,inΩ.
Multiplying (30) by ζN and integrating over Ω and by parts, we have:
(33)
12ddt||ζN||12+ζN2+[fN(ςN)¯,ζN]+[η(ςN),(Δ1)1ζN]=0.
Since
Ω(Δ)1ζNtζNdx=12ddtΩ(Δ)1ζN2dx=12ddt||ζN||12
and
ΩΔζNζNdx=ΩζNζNdxΓζNνζNds=||ζN||2.
Note that
[fN(ςN)¯,ζN]=[fN(ςN)fN(ςN),ζN]
and taking s = ζN, m = 〈ςN〉 in (17), we get
(34)
[fN(ςN)¯,ζN]c4ΩζN4+ςN2ζN2dxc.
Indeed, from (17), we have
fN(s+m)fN(m)sc4s4+m2s2c5fN(ςN)fNςNζNc4ζN4+ςN2ζN2c5,
so
[fN(ςN)fNςN,ζN]=ΩfN(ςN)fNςNζNdxc4ΩζN4+ςN2ζN2dxc5.
Furthermore,
|[η(ςN)¯,(Δ1)ζN]|=|[η(ςN)η(ςN),(Δ1)ζN]]|c||ζN||||η(ςN)g(ςN)||,
by Cauchy Schwartz and using ||ζN||−1c||ζN|| which results after reapplying Lemma (1) with s = ζN and m = 〈ςN〉 and Young’s inequality:
(35)
|[η(ςN)¯,(Δ1)ζN]|c44ΩζN4+ςN2ζN2dx+c||ζN||2c44ΩζN4+ςN2ζN2dx+c.
Indeed, we have that
|[η(ςN)¯,(Δ1)ζN]|c||ζN||||η(ςN)η(ςN)||c||ζN||22+||η(ςN)η(ςN)||22c2||ζN||2+c9ΩζN4+ςN2ζN2+ζN2dx+c10c42ΩζN4+ςN2ζN2dx+c||ζN||2+cc42ΩζN4+ςN2ζN2dx+c.
It follows from (33)(35), that
(36)
ddt||ζN||12+c||ζN||H1(Ω)2+ΩζN4+ςN2ζN2dxc,c>0.
Since
12ddt||ζN||12+||ζN||2=[fN(ςN)¯,ζN][η(ςN)¯,Δ1ζN]c4ΩζN4+ςN2ζN2dx+c+c42ΩζN4+ςN2ζN2dx+c.
Next, multiplying (30) by −ΔζN and integrating over Ω, we obtain
(37)
12ddt||ζN||2+||ΔζN||2+[fN(ςN)¯,ΔζN]+[η(ςN)¯,ζN]=0.
In fact, we have
ΩΔ1ζNt(ΔζN)dx=ΩζNtζNdx=12ddtΩζN2dx=12ddt||ζN||2.
Furthermore, owing to (14)
(38)
[fN(ςN)¯,ΔζN]=[fN(ςN),ΔζN]=ΩfN(ςN)ΔζNdx=ΩfN(ςN).ζNdx=Ωf(ςN)ςNζNdx=[f(ςN)ςN,ζN]λ1||ζN||2
and owing once more to Lemma (1), we have
(39)
|[η(ςN)¯,ζN]|=|[η(ςN)η(ςN),ζN]|12||ΔζN||2+cΩζN4+ςN2ζN2dx+c.
Indeed,
|[η(ςN)η(ςN),ζN]|||η(ςN)η(ςN)||||ζN||||ζN||22+||η(ςN)η(ςN)||2212||ΔζN||2+cΩζN4+ςN2ζN2dx+c.
From (37)(39) it follows that
(40)
ddt||ζN||2+||ΔζN||2c||ζN||H1(Ω)2+ΩζN4+ςN2ζN2dx+c.
By (37), we have
12ddt||ζN||2+||ΔζN||2=[fN(ςN)¯,ΔζN][η(ςN)¯,ζN]λ1||ζN||2+12||ΔζN||2+cΩζN4+ςN2ζN2dx+c,
so,
ddt||ζN||2+||ΔζN||2c||ζN||2+ΩζN4+ςN2ζN2dx+c.
Finally, summing (36) and γ1 times (40), where γ1 > 0 is small enough and independent of N, we find
(41)
ddt||ζN||12+γ1||ζN||2+c||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dxc,c>0.
Indeed, we have (36)+γ1(40) gives
ddt||ζN||2+γ1||ζN||2+c||ζN||H1(Ω)+γ1||ΔζN||2+cΩζN4+ςN2ζN2dxc,
then
ddt||ζN||2+γ1||ζN||2+c||ζN||H2(Ω)+ΩζN4+ςN2ζN2dxc.
We now come back to (25)(26). Noting that g(s) ≥ psp, we have
dςNdt+η(ςN)=ζN20dςNdtη(ςN)pςN+pdςNdt+pςNp.
Consider the ODE:
dςNdt+pςN=p,
then
dςNdt=pςN1,
hence
dςNςN1=pdt,
we infer
ln|ςN1|=pt+k,
so
ςN=cept+1,
but at t = 0, 〈ςN〉 = 〈ς0〉, hence c = 〈ς0〉 − 1.

Finally,

(42)
ςN(t)ς01ept+1,
as long as it exists. In particular,
(43)
ςN(t)<1.
Note that it follows from (41) that:
ddt||ζN||12+γ1||ζN||2+c||ζN||12+γ1||ζN||2c,c>0.
Indeed, we have that
c||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dxc||ζN||H(Ω)212||ΔζN||2cc||ΔζN||2cc||ζN||2cc2||ζN||2+c2||ζN||2cc||ζN||12+γ1||ζN||2c,
but by (41)
ddt||ζN||12+γ1||ζN||2+c||ζN||12+γ1||ζN||2ddt||ζN||12+γ1||ζN||2+c||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dx+c2c.
Which yields
(44)
||ζN(t)||2cect||ζ0||2+c,c>0.
In fact,
ddt||ζN||12+γ1||ζN||2+c||ζN||12+γ1||ζN||2c,c>0,
then by Gronwall lemma
||ζN||12+γ1||ζN||2||ζ0||12+γ1||ζ0||2+cγ1||ζN||2ect||ζ0||12+γ1||ζ0||2+c||ζN||21γ1ect||ζ0||12+γ1||ζ0||2+cγ1,
but ||ζ0||12q||ζ0||2 , then
||ζN||21γ1ectq||ζ0||2+γ1||ζ0||2+cγ1cect||ζ0||2+c.
As long as it exists, in particular
ζN2=k||ζN2(t)||c||ζ0||2+c,sinceect1,
and ζ0 = ς0 − 〈ς0〉 and |〈ς0〉| ≤ 1 − 2δ, so
(45)
ζN2(t)c(ς0,δ),
as long as it exists.

Let y± be the solution of the Ricatti ODE’s

(46)
y++η(y+)=0,y+(0)=ς0
(47)
y+η(y)=c(ς0,δ),y(0)=ς0,
where c(ς0, δ) is the constant in (45). Then it follows from the comparison principle that, as long as this makes sense
(48)
y(t)ςN(t)y+(t).
Indeed, we have that
dςNdt+g(ςN)=ζN20,
so, 〈ςN (t)〉 ≤ y+(t), also
ζN2c(ς0,δ),
hence
dςNdt+η(ςN)c(ς0,δ),
so 〈ςN (t)) ≥ y(t).

In particular, it follows that (at least) a local in times solution exists on some [0, T ], where T > 0 is independent of N. Note also that

y+(t)=y2cy1etc01cetc0,
with
y1=p+p2+4p2,y2=pp2+4p2
and
c=y2ς0y1ς0.
y+(t) is the solution of the ODE: y′ + η(y) = 0, so y′ + y2p(1 − y) = 0, so
dydt=p+pyy2dyp+pyy2=dt.
We have
p+pyy2=0:Δ=p24(p)(1)=p2+4p,
hence the roots of the quadratic equation are
y1=pp2+4p2=y1=p+p2+4p2,y2=p+p2+4p2=y2=pp2+4p2,
so
dy(yy1)(yy2)=t+c,1(yy1)(yy2)=Ayy1+Byy2.
Where
A=limyy11yy2=1y1y2=1p2+4p=c0,B=limyy21yy1=1y2y1=1p2+4p=c0.
We infer
c0yy1+c0yy2dt=t+c,c0ln|yy2|ln|yy1|=t+lnc,c0ln|yy2yy1|=t+lnc,ln|yy2yy1|c0=t+lnc,yy2yy1c0=cet,yy2yy1=cetc0,yy2=cetc0(yy1),y1cetc0=y2cy1etc0,y=y2cy1etc01cetc0.
But y|t=0 = 〈ς0〉, so
ς0=y2cy11c,y2cy1=ς01c,y2ς0=cy1ς0,c=y2ς0y1ς0.
We assume from now on that t ∈ [0, T ], where T is as above, we again multiply (30) by ζN and we have
12ddt||ζN||12+||ζN||2+[fN(ςN),ζN]cΩζN4+ςN2ζN2dx+c,
since by (33)
(49)
12ddt||ζN||12+||ζN||2+[fN(ςN)¯,ζN]=[η(ςN)¯,Δ1ζN]cΩζN4+ςN2ζN2dx+c.
Which yields, employing (18) with s = ζN and m = 〈ςN〉,
(50)
ddt||ζN||12+cδ||fN(ςN)||L1(Ω)+ΩFN(ςN)dxcΩζN4+ςN2ζN2dx+cδ,cδ>0.
In fact, we know from (18) that
fN(ςN)ζNcδFN(ςN)+|f1,N(ςN)|cδΩfN(ςN)ζNdxcδΩFN(ςN)dx+Ω|f1,N(ςN)|dxcδ,
12ddt||ζN||12+cδ||f1,1(ςN)||L1(Ω)+ΩFN(ςN)dxcδcΩζN4+ςN2ζN2dx+c,
but f1(ςN) = fN (ςN) + λςN. We then infer that
ddt||ζN||12+cδ||fN(ςN)||L1(Ω)+ΩFN(ςN)dxcΩζN4+ςN2ζN2dx+cδ,cδ>0.
Summing (41) and γ2× (50), where γ2 > 0 is small enough and independent of N and δ, we obtain a differential inequality of the form
(51)
dE1,Ndt+cδE1,N+||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dx+||fN(ςN)||L1(Ω)+ΩFN(ςN)dxcδ,cδ>0,
where E1,N=(1+γ2)||ζN||12+γ1||ζN||2 .

In fact, (41)+γ2(50) give

ddt||ζN||12+γ1||ζN||2+c||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dx+γ2ddt||ζN||12+γ2cδ||fN(ςN)||L1(Ω)+ΩFN(ςN)dxc+γ2cΩζN4+ςN2ζN2dx+γ2cδ,cδ>0.
Hence,
dE1,Ndt+cδ||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dx+||fN(ςN)||L1(Ω)+ΩFN(ςN)dxcδ,cδ>0,
but
E1,N=(1+γ2)||ζN||12+γ1||ζN||2(1+γ2)k||ζN||H2(Ω)2+γ1k||ζN||H2(Ω)2,
so,
E1,Nk||ζN||H2(Ω)2,
then
dE1,Ndt+cδE1,N+||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dx+||fN(ςN)||L1(Ω)+ΩFN(ςN)dxcδ,cδ>0.
If we note that |〈ςN〉 ≤ 1, we see that
dςN2dt=2ςNζN2ςN2+p(1ςN)c||ζN||2,
which results in the following
(52)
dςN2dt+ςN2c||ζN||2+c,
since
dςN2dt=2ςNddtςN=2ςNg(ςN)ζN2=2ςNςN2+p(1ςN)ζN2=2ςN3+2pςN2pςN22ςNζN2c||ζN||2+c,
so
dςN2dt+ςN2c||ζN||2+c+1c||ζN||2+c.
Summing (51) and γ3 × (52), where γ3 > 0 (independent of N) is small enough, we get
(53)
dE2,Ndt+cδE2,N+||ςN||H2(Ω)2+ΩζN4+ςN2ζN2dx+||fN(ςN)||L1(Ω)+ΩFN(ςN)dxcδ,cδ>0,
where
E2,N=E1,N+γ3ςN2,
since (51) +γ3 (52) give
ddtE1,N+cδE1,N+||ζN||H2(Ω)2+ΩζN4+ςN2ζN2dx+||fN(ςN)||L1(Ω)+ΩFN(ςN)dx+γ3ddtςN2+γ3ςN2cδ+cγ3||ζN||2+γ3c,
but
||ζN||2=ΩζN2dxcΩζN4dx,
so we get (53).

E2,N satisfies

c||ςN||2E2,Nc||ςN||2,c,c>0.
Indeed, we have
E2,N=E1,N+γ3ςN2=(1+γ2)||ζN||12+γ1||ζN||2+γ3ςN2,
but ||ζN||−1 ∼ ||ζN||L2(Ω), since 〈ζN〉 = 0, so ∃c1, c2 > 0, such that
c1||ζN||L2(Ω)2||ζN||12c2||ζN||L2(Ω)2.γ3ςN2+(1+γ2)c1||ζN||L2(Ω)2+γ1||ζN||2E2,N(1+γ2)c2||ζN||L2(Ω)2+γ1||ζN||2+γ3ςN2c3||ζN||L2(Ω)2+ςN2E2,Nc4||ζN||L2(Ω)2+ςN2,
then
c||ςN||2E2,Nc||ςN||2.
In the next step, we multiply (30) by dςNdt , then integrate over Ω and have
(54)
||dζNdt||12+12ddt||ςN||2+[fN(ςN),dςNdt]+[ςN2p(1ςN),(Δ)1dςNdt]=0.
Indeed, (30) results in
(Δ)1dςNdtΔζN+fN(ςN)¯+(Δ)1η(ςN)¯=0,
but
ΩΔζNdζNdtdx==12ddtΩζNζNdxΓζNζNνds=12ddt||ζN||2.
Furthermore
(55)
[fN(ςN),ζNt]=[fN(ςN),ςNt][fN(ςN),ςNt]=ddtΩFN(ςN)dx+[fN(ςN),ζN2+ςN2p(1ςN)]=ddtΩFN(ςN)dx+Vol(Ω)fN(ςN)[ζN2+ςN2p(1ςN)]||fN(ςN)||L1(Ω)||ζN||L2(Ω)2+1.
We also note that
(56)
|[ςN2p(1ςN),(Δ)1ζNt]|=[ςN2ςN2+p(ςNςN),(Δ)1ζNdt]12||ζNt||12+cΩζN4+ςN2ζN2dx+c.
It follows from (54)(56) that
(57)
ddt||ζN||2+2ΩFN(ςN)dx+||ζNt||12c||fN(ςN)||L1(Ω)||ζN||2+1+ΩζN4+ςN2ζN2dx.
By (54)
||ζNt||12+12ddt||ζN||2=[fN(ςN),ζNt][ςN2p(1ςN),(Δ)1ςNt]ddtΩFN(ςN)dx+c||fN(ςN)||L1(Ω)||ζN||2+1+12||ζNt||12+cΩζN4+ςN2ζN2dx,
then
12||ζNt||12+12ddt||ζN||2+ddtΩFN(ςN)dxc||fN(ςN)||L1(Ω)||ζN||2+1+ΩζN4+ςN2ζN2dx,
and next we multiply by 2 and get (57). It follows from (53) that ςN is bounded in L(0, T ; L2(Ω))∩L2(0, T ; H2(Ω)), and ΩζN4+ςN2ζN2dx is bounded in L1(0, T) which implies that ςN is bounded in L4((0, T) × Ω) and fN (ςN) is bounded in L1((0, T) × Ω) independently of N. It therefore follows from (57) that ςN is also bounded in L(0, T ; H1(Ω)) and ςNt is bounded in L2(0, T ; H−1(Ω)) independently of N (note that FN is bounded on [−1, 1], independently of N).

We finally multiply (30) by fN(ςN)¯ and integrate over Ω and have

||fN(ςN)¯||2[ΔζN,fN(ςN)¯]+[(Δ)1ζNt,fN(ςN)¯]+[(Δ)1η(ςN)¯,fN(ςN)¯]=0,
noting that
[ΔζN,fN(ςN)¯]=[ΔζN,fN(ςN)]=[fN(ςN)ςN,ςN]λ1||ςN||2.
Indeed, we have that
[ΔζN,fN(ςN)¯]=[ΔζN,fN(ςN)fN(ςN)]=[ΔζN,fN(ςN)]=ΩΔςNfN(ςN)dx=ΩςNfN(ςN)dx=ΩςN(ςN)fN(ςN)dxλ1||ςN||2.
Proceeding as above, we get the inequality
(58)
||fN(ςN)¯||2c||ςN||H1(Ω)2+ΩζN4+ςN2ζN2dx+||ζNt||12.
Indeed, we have that
|[Δ1ζNt,fN(ςN)¯]|||Δ1ζNt||||fN(ςN)¯||ε2||ζNt||12+12ε||fN(ςN)¯||2|[Δ1η(ςN)¯,fN(ςN)¯]|Δ1η(ςN)¯||fN(ςN)¯||ε2||Δ1η(ςN)¯||2+12ε||fN(ςN)¯||2c||η(ςN)¯||2+||fN(ςN)¯||2cΩζN4+ςN2ζN2dx+c+12ε||fN(ςN)¯||2.
Therefore
||fN(ςN)¯||2=[ΔζN,fN(ςN)¯][(Δ)1ζNt,fN(ςN)¯]λ1||ςN||2+ε2||ζNt||12+12ε||fN(ςN)¯||2+cΩζN4+ςN2ζN2dx+c+12ε||fN(ςN)¯||2,
and we get (58).

This results in a uniform (with respect to N) estimate for fN(ςN)¯ in L2((0, T) × Ω). From (18) it follows that

(59)
|fN(ςN)|cδζN||fN(ςN)¯||+cδ,
we find a uniform (with respect to N) estimate for fN (ςN) in L2((0, T) × Ω).

Besides, owing to (18) with 〈ςN〉 = m and ζN = s,

fN(ςN)ςNc6FN(ςN)+|f1,N(ςN)|c7|f1,N(ςN)|1c6fN(ςN)ζNFN(ςN)+c7c6
|f1,N(ςN)||f1,N(ςN)|1c61Vol(Ω)ΩfN(ςN)ζNdx1Vol(Ω)ΩFN(ςN)dx+c7c6,
but FN (ςN) ≤ c f (ςN)ςN + | f1,N (ςN)| and fN (ςN) = f1,N (ςN) − λ1ςN.
|fN(ςN)||f1,N(ςN)|+λ1|ςN||f1,N(ςN)|+c||ςN||L2(Ω)c||ςN||L2(Ω)+||fN(ςN)¯||.

3.2. Existence of solutions

We have the following theorems.

Theorem 2

We assume that ς0H1(Ω) is such that |〈ς0〉| < 1 and −1 < ς0(x) < 1 a.e., x ∈ Ω, then there exists T = T (ς0) > 0 and a solution of (7)(9) on [0, T ] such that ςC([0, T ]; H1(Ω)) ∩ L2(0, T ; H2(Ω)) ∩ L4((0, T) × Ω) and ςtL2(0,T;H1(Ω)) .

Furthermore, −1 < ς(x, t) < 1 a.e. (x, t) ∈ Ω × (0, T).

The proof of this theorem is standard due to the uniform estimates obtained in the previous section.

Theorem 3

Assume that the same assumptions apply as in Theorem 2, then the solution ς is global in time.

Proof

Consider [0, T), such that T > 0 is the maximal time interval in which the solution ς is given in Theorem 2 exists, so that

|ς(x,t)|1a.e.(x,t)Ω×[0,T).
Furthermore, 〈ς〉 satisfies
dςdt+ς2p(1ς)=0.
Using the fact that
dςdt+pς=ς21,
which yields
ς(t)=eptς0ept0tepsς21dx.
Noting that
|ς21|2,
this yields
|ς(t)|eptς0+1ept,t[0,T).
In particular, it follows from the last inequality that
|ς(x,t)|1,t[0,T).

4. Conclusions

In this study, we examined a variation of the Cahn-Hilliard equation featuring a logarithmic nonlinear term and a proliferation term given by η(s) = s2p(1 − s). The model, subject to Neumann boundary conditions, captures interactions between liquid and gas, with p denoting the gas pressure. Specifically, the model finds application in understanding the formation of islands. We successfully demonstrated the existence of a solution to the problem. Notably, our challenge stemmed from the singularities in the nonlinear terms. Constructing approximated problems posed difficulty, as we could not rule out the possibility of solutions to these approximated problems experiencing blowup in finite time. Consequently, deriving uniform estimates for the approximated problems in the presence of singularities became a more intricate task.

It is noteworthy that our future work will delve into the exploration of the Cahn-Hilliard equation incorporating a fidelity term of the form λ0χΩ\D(x)(uh). Here, λ0 stands as a suitably large constant, and D represents the inpainting model. The results indicate that inpainting in this scenario is faster and more efficient compared to a model with a regular polynomial nonlinear term.

5. Declarations

5.1. Conflict of interest 

Not applicable.

5.2. Funding

Not applicable.

5.3. Author’s contribution

H.F.-Data Curation, Conceptualization, Design, Formal Analysis, Project Administration. M.B.-Data Curation, Conceptualization, Design. H.A.-Writing - Original Draft, Investigation. Y.A.-Writing - Original Draft, Resources. All authors reviewed the results and approved the final version of the manuscript.

5.4. Acknowledgement

The authors wish to thank the referees for their careful reading of the article and useful comments.

5.5. Data availability statement

All data that support the findings of this study are included within the article.

5.6. Using of AI tools

The authors declare that they have not used Artificial Intelligence (AI) tools in the creation of this article.

Language: English
Page range: 83 - 102
Submitted on: Nov 12, 2023
Accepted on: Jan 20, 2024
Published on: Jun 2, 2024
Published by: Harran University
In partnership with: Paradigm Publishing Services
Publication frequency: 2 issues per year

© 2024 Hussein Fakih, Marwa Badreddine, Hawraa Alsayed, Yahia Awad, published by Harran University
This work is licensed under the Creative Commons Attribution 4.0 License.