1Introduction
Physical sciences rely heavily on nonlinear partial differential equations (PDEs), which are engaged in complex nonlinear physical mechanisms. The generalized CZK equations are significant models for a wide range of physical phenomena, including shallow and multilayered internal waves, ion-acoustic waves, plasma physics, hydrodynamics, and waves in nonlinear LC circuits by way of mutual inductance among surrounding inductors and many others [1,2,3,4]. Several disciplines of applied sciences and engineering make use of generalized CZK equations. As many natural phenomena, including vibration and self-reinforcing solitary waves, they are characterized by exact solutions of nonlinear coupled PDEs. These models can play a vital role in the understanding of these physical phenomena. As a result, the work of determining the exact solutions has become essential and significant in nonlinear science. Both mathematicians and physicists have put a lot of effort into this subject in recent years and have demonstrated a variety of helpful techniques, such as Hirota’s bilinear technique [5], the mapping method [6], the reciprocal Bäcklund transformation method [7], the homogeneous balance mechanism [8], the Painleve expansion [9], the Exp-function approach [10], the Jacobi elliptic function expansion method [11, 12], the rational expansion approach [13] and numerous other methods [14, 15] are just a few of them.
Initially, the Zakharov Kuznetsov (ZK) equation [16] was developed to describe lossless plasma with strongly magnetized, weakly nonlinear ion-acoustic waves in two dimensions. In order to properly consider the nonlinear water wave model in a coastal design, seaport, and other areas, civil engineers, coastal, need to have a solid understanding of the solutions to such PDEs. Hence, a key interest in fluid dynamics is finding various kinds of exact solutions to these equations. Many articles have been written to locate the exact and numerical solutions to these equations. The ZK equation, the modified ZK equation, and the extended forms of these equations have all been studied for exact solutions using various methodologies [16,17,18,19,20]. The fractional form of the ZK equation was studied by [21]. Here, we take a look at a CZK equation [22] that is described as
(1)
\begin{array}{*{20}{r}}{{\mu _t} + {\mu _{xxx}} + {\mu _{yyx}} - 6\mu {\mu _x} - {\nu _x} = 0,}\\{{\nu _t} + {\alpha _1}{\nu _{xxx}} + {\alpha _2}{\nu _{yyx}} + {\alpha _3}{\nu _x} - 6{\alpha _4}\nu {\nu _x} - {\alpha _5}{\mu _x} = 0,}\end{array}
where α1, α2, α3, α4 and α5 are arbitrary parameters, μ, ν are dependent variables and x, y, t are independent variables. In these equations, the initial term represents the system’s evolution, while the combination of the second and third terms accounts for dispersion effects. The second-to-last term in the first equation and the fifth term in the second equation are related to convection, while the final terms, along with the fourth term in the second equation are wedge terms, introduce coupling between different aspects of the system. Solitons emerge due to a delicate equilibrium between dispersion and nonlinearity, where these waves maintain their shape and amplitude while propagating through the medium. The use of symmetry approaches to deal with the precise solutions of the nonlinear CZK equations is interesting as it provides a systematic algorithm.
Symmetry analysis [23,24,25,26,27,28] is a mathematical technique used to study and understand the symmetries inherent in equations or physical systems. Symmetries represent invariance properties under certain transformations. In the context of differential equations, symmetry analysis involves identifying transformations (often generated by Lie groups) that leave the equation unchanged or transform it into an equivalent form. These symmetries can reveal valuable information about the equations and may lead to simplified solutions. An optimal system of Lie subalgebra [29,30,31] refers to a specific set of subalgebras that are particularly useful for analyzing the symmetries of a given mathematical equation or system. These subalgebras are chosen in a way that simplifies the symmetry analysis and allows for the most efficient reduction of the equation. This systematic approach aids in identifying the key symmetries that can help solve the equation or uncover important properties. Invariant solutions are solutions to a differential equation or mathematical problem that remain unchanged (invariant) under certain symmetrical transformations. These solutions are particularly valuable because they can simplify complex equations and make them more tractable. Invariant solutions are often derived by exploiting the symmetries of the equation, which reduces the problem to a more manageable form.
The importance of Lie theory in nonlinear and engineering disciplines is enormous, and it has numerous uses. At the present day, there is a wealth of literature on Lie theory [32,33,34,35,36,37,38]. Many well-known nonlinear PDEs can only be solved with symmetry methods. We use symmetry approaches to accomplish our objectives since we are interested in exact solutions to the nonlinear CZK equations (1). To our knowledge, there is no prior documentation regarding the solutions we found here. Our obtained solutions exhibit a unique form of wave behavior, where waves travel at a constant speed while maintaining their characteristics, and can be used in the theory of waves. We shall plot the results acquired here to emphasize their physical significance.
The following sections serve as an introduction to the technique and problem discussed in this article. In Section 2, the Lie symmetry approach is explained along with some findings for optimal systems that make use of the Lie algebra that was acquired as the basis. Potential similarity reductions for the CZK equations are covered in Section 3. In Section 4, we examine the step response for the structural dynamics of the presented solutions. In Section 5, we investigate the solution profiles for the CZK equations (1). In Section 6, we introduce our analysis.
2Symmetries and classification of the invariant solutions
In this section, we will explore the Lie symmetries and optimal system of equation (1). Consider the one-parameter Lie group of transformation
(2)
\begin{array}{*{20}{r}}{\tilde x \to x + \varsigma {\varphi _1}(x,y,t,\mu ,\nu ) + O({\varsigma ^2}),}\\{\tilde y \to x + \varsigma {\varphi _2}(x,y,t,\mu ,\nu ) + O({\varsigma ^2}),}\\{\tilde t \to t + \varsigma {\varphi _3}(x,y,t,\mu ,\nu ) + O({\varsigma ^2}),}\\{\tilde \mu \to \mu + \varsigma {\rho _1}(x,y,t,\mu ,\nu ) + O({\varsigma ^2}),}\\{\tilde \nu \to x + \varsigma {\rho _2}(x,y,t,\mu ,\nu ) + O({\varsigma ^2}),}\end{array}
where ς is the group parameter. The infinitesimal generator associated with the above transformations is
(3)
Q = {\varphi _1}(x,y,t,\mu ,\nu )\frac{\partial }{{\partial x}} + {\varphi _2}(x,y,t,\mu ,\nu )\frac{\partial }{{\partial y}} + {\varphi _3}(x,y,t,\mu ,\nu )\frac{\partial }{{\partial t}} + {\rho _1}(x,y,t,\mu ,\nu )\frac{\partial }{{\partial \mu }} + {\rho_2}(x,y,t,\mu ,\nu )\frac{\partial }{{\partial \nu }}.
The coefficient functions ϕ1,ϕ2,ϕ3,ρ1 and ρ2 are to be found, and the operator Q fulfills the Lie symmetry condition
(4)
\begin{array}{*{20}{l}}{{Q^{[3]}}({\mu _t} + {\mu _{xxx}} + {\mu _{yyx}} - 6\mu {\mu _x} - {\nu _x}{{)|}_{(1)}} = 0,}\\{{Q^{[3]}}({\nu _t} + {\alpha _1}{\nu _{xxx}} + {\alpha _2}{\nu _{yyx}} + {\alpha _3}{\nu _x} - 6{\alpha _4}\nu {\nu _x} - {\alpha _5}{\mu _x}{{)|}_{(1)}} = 0,}\end{array}
where Q[3] is the third extension of Q.
By solving equation (4), we obtain the expressions for infinitesimals ϕ1,ϕ2,ϕ3,ρ1 and ρ2 which leads to four symmetry generators given by,
(5)
{Q_1} = \frac{\partial }{{\partial t}},\quad {Q_2} = \frac{\partial }{{\partial x}},\quad {Q_3} = \frac{\partial }{{\partial y}},\quad {Q_4} = t\frac{\partial }{{\partial x}} - \frac{1}{6}\frac{\partial }{{\partial \mu }} - \frac{1}{{6{\alpha _4}}}\frac{\partial }{{\partial \nu }}.
Under the bracket operator, the commutator Table 1 is defined as
[{Q_i},{Q_i}] = {Q_i}{Q_j} - {Q_j}{Q_i}.
Table 1
Commutator table.
| [Qi,Qj] | Q1 | Q2 | Q3 | Q4 |
|---|
|
|---|
| Q1 | 0 | 0 | 0 | Q2 |
| Q2 | 0 | 0 | 0 | 0 |
| Q3 | 0 | 0 | 0 | 0 |
| Q4 | −Q2 | 0 | 0 | 0 |
The adjoint representation Table 2 is given by
(6)
Ad(\exp (\varepsilon {{Q}_{i}}).{{Q}_{j}})={{Q}_{j}}-\varepsilon [{{Q}_{i}},{{Q}_{j}}]+\frac{{{\varepsilon }^{2}}}{2!}[{{Q}_{i}},[{{Q}_{i}},{{Q}_{j}}]]-\cdots .
Table 2
Adjoint table.
| [Qi,Qj] | Q1 | Q2 | Q3 | Q4 |
|---|
|
|---|
| Q1 | Q1 | Q2 | Q3 | Q4 − ɛQ2 |
| Q2 | Q1 | Q2 | Q3 | Q4 |
| Q3 | Q1 | Q2 | Q3 | Q4 |
| Q4 | Q1 + ɛQ2 | Q2 | Q3 | Q4 |
Theorem 1
Let ℒ4 be the Lie algebra of equation (1) with basis (5). The optimal system of one-dimensional subalgebras is then generated by the following generators:
(7)
\begin{array}{*{20}{l}}{{\mathcal{M}^1}}&{ = \langle {Q_2}\rangle ,}\\{{\mathcal{M}^2}}&{ = \langle {Q_3}\rangle ,}\\{{\mathcal{M}^3}}&{ = \langle {Q_2} + \beta {Q_3}\rangle ,\beta \ne 0,}\\{{\mathcal{M}^4}}&{ = \langle {Q_1}\rangle ,}\\{{\mathcal{M}^5}}&{ = \langle {Q_1} + \beta {Q_3}\rangle ,\beta \ne 0,}\\{{\mathcal{M}^6}}&{ = \langle {Q_4}\rangle ,}\\{{\mathcal{M}^7}}&{ = \langle {Q_3} + \beta {Q_4}\rangle ,\beta \ne 0,}\\{{\mathcal{M}^8}}&{ = \langle {Q_1} + \beta {Q_4}\rangle ,\beta \ne 0,}\\{{\mathcal{M}^9}}&{ = \langle {Q_1} + \beta {Q_3} + \gamma {Q_4}\rangle , \beta ,\gamma \ne 0.}\end{array}
Proof
Consider a general element Q ∈ ℒ4. We have,
(8)
Q = {k_1}{Q_1} + {k_2}{Q_2} + {k_3}{Q_3} + {k_4}{Q_4}.
Case 1: k4 = 0, k1 = 0,k3 = 0. Then, we have
(9)
Q = {k_2}{Q_2}.
We get
(10)
{\mathcal{M}^1} = {Q_2}.
Case 2: k4 = 0, k1 = 0,k3 ≠ 0,k2 = 0. Then, we have
(11)
Q = {k_3}{Q_3}.
We get
(12)
{\mathcal{M}^2} = {Q_3}.
Case 3: k4 = 0, k1 = 0,k3 ≠ 0,k2 ≠ 0. Then, we have
(13)
Q = {k_2}{Q_2} + {k_3}{Q_3}.
Take k2 = 1, then, we have
(14)
{\mathcal{M}^3} = {Q_2} + \beta {Q_3}, \beta \ne 0.
Case 4: k4 = 0, k1 ≠ 0,k3 = 0. Then, we have
(15)
Q = {k_1}{Q_1} + {k_2}{Q_2},
(16)
{Q}'=Ad({{e}^{\varepsilon }}{{Q}_{4}})Q={{k}_{1}}{{Q}_{1}},
(17)
{\mathcal{M}^4} = {Q_1}.
Case 5: k4 = 0, k1 ≠ 0,k3 ≠ 0,k1 = 1. Then, we have
(18)
Q = {Q_1} + {k_2}{Q_2} + {k_3}{Q_3},
(19)
{Q}'=Ad({{e}^{\varepsilon }}{{Q}_{4}})Q={{Q}_{1}}+{{k}_{3}}{{Q}_{3}},
(20)
{\mathcal{M}^5} = {Q_1} + \beta {Q_3}, \beta \ne 0.
Case 6: k4 ≠ 0, k1 = 0,k3 = 0. Then, we have
(21)
Q = {k_2}{Q_2} + {k_4}{Q_4},
(22)
{Q}'=Ad({{e}^{\varepsilon }}{{Q}_{1}})Q={{k}_{4}}{{Q}_{4}},
(23)
{\mathcal{M}^6} = {Q_4}.
Case 7: k4 ≠ 0, k1 = 0,k3 ≠ 0. Then, we have
(24)
Q = {k_2}{Q_2} + {k_3}{Q_3} + {k_4}{Q_4},
(25)
{Q}'=Ad({{e}^{\varepsilon }}{{Q}_{1}})Q={{k}_{3}}{{Q}_{3}}+{{k}_{4}}{{Q}_{4}}.
Take k3 = 1, Then, we have
(26)
{\mathcal{M}^7} = {Q_3} + \beta {Q_4}, \beta \ne 0.
Case 8: k4 ≠ 0, k1 ≠ 0,k3 = 0,k1 = 1. Then, we have
(27)
Q = {Q_1} + {k_2}{Q_2} + {k_4}{Q_4},
(28)
{Q}'=Ad({{e}^{\varepsilon }}{{Q}_{4}})Q={{Q}_{1}}+{{k}_{4}}{{Q}_{4}},
(29)
{\mathcal{M}^8} = {Q_1} + \beta {Q_4}, \beta \ne 0.
Case 9: k4 ≠ 0, k1 ≠ 0,k3 ≠ 0,k1 = 1. Then, we have
(30)
Q = {Q_1} + {k_2}{Q_2} + {k_3}{Q_3} + {k_4}{Q_4},
(31)
{Q}'=Ad({{e}^{\varepsilon }}{{Q}_{4}})Q={{Q}_{1}}+{{k}_{3}}{{Q}_{3}}+{{k}_{4}}{{Q}_{4}},
(32)
{\mathcal{M}^9} = {Q_1} + \beta {Q_3} + \gamma {Q_4}, \beta ,\gamma \ne 0.
3Invariant solutions by similarity transformations
In this section, we find the invariant group solutions under the reduction of different symmetries.
3.1Reduction by 〈ℳ1,ℳ2〉 = 〈Q2,Q3〉
First, consider the vector field
{Q_2} = \frac{\partial }{{\partial x}}
. We get the similarity transformations μ = f (r,s),v = g(r,s), where r = t,s = y. Using these transformations, we obtain the reduced system given by,
(33)
\begin{array}{*{20}{l}}{{f_r} = 0,}\\{{g_r} = 0.}\end{array}
Now, take
{Q_3} = \frac{\partial }{{\partial y}}
. Q3 in new variables can be written as
{\tilde Q_3} = \frac{\partial }{{\partial s}}
. The similarity variables are written as, f = θ (z),g = ϑ (z) where z = r. The reduced ODE system obtained by using above transformations is given by,
(34)
\begin{array}{*{20}{l}}{\theta ' = 0,}\\{\vartheta ' = 0,}\end{array}
this implies,
(35)
\begin{array}{*{20}{l}}{\theta = {c_1},}\\{\vartheta = {c_2}.}\end{array}
So, we get
(36)
\begin{array}{*{20}{l}}{f = {c_1},}\\{g = {c_2}.}\end{array}
Hence, the invariant solution of Eq. (1) in original variables becomes
(37)
\begin{array}{*{20}{l}}{{\mu _1}(x,y,t) = {c_1},}\\{{\nu _1}(x,y,t) = {c_2}.}\end{array}
3.2Reduction by 〈ℳ4,ℳ3〉 = 〈Q1,Q2 +β Q3〉
First, consider the vector field
{Q_1} = \frac{\partial }{{\partial t}}
. We get the similarity transformations μ = f (r,s),v = g(r,s), where r = x,s = y. Using these transformations, we obtain the reduced system given by,
(38)
\begin{array}{*{20}{r}}{{\alpha _1}{g_{rrr}} + {\alpha _2}{g_{rss}} + ({\alpha _3} - 6{\alpha _4}g){g_r} - {\alpha _5}{f_r} = 0,}\\{ - 6f{f_r} + {f_{rrr}} + {f_{rss}} - {g_r} = 0.}\end{array}
Now, take
{Q_2} + \beta {Q_3} = \frac{\partial }{{\partial x}} + \beta \frac{\partial }{{\partial y}}
. Q2 + β Q3 in new variables can be written as
{\tilde Q_2} + \beta {\tilde Q_3} = \frac{\partial }{{\partial r}} + \beta \frac{\partial }{{\partial s}}
. The similarity variables are written as, f = θ (z),g = ϑ (z) where z = −β r + s. The reduced ODE system obtained by using above transformations is given by,
(39)
\begin{array}{*{20}{r}}{ - \beta (({\alpha _1}{\beta ^2} + {\alpha _2})\vartheta ''' + ({\alpha _3} - 6{\alpha _4}\vartheta )\vartheta ' + {\alpha _5}\theta ') = 0,}\\{ - \beta ({\beta ^2}\theta ''' - 6\theta \theta ' - \vartheta ' + \theta ''') = 0.}\end{array}
Since β ≠ 0. It follows that,
(40)
\begin{array}{*{20}{r}}{({\alpha _1}{\beta ^2} + {\alpha _2})\vartheta ''' + ({\alpha _3} - 6{\alpha _4}\vartheta )\vartheta ' + {\alpha _5}\theta ' = 0,}\\{{\beta ^2}\theta ''' - 6\theta \theta ' - \vartheta ' + \theta ''' = 0.}\end{array}
We can furnish the solution of (40) by the tanh ansatz [39]
(41)
\theta (z) = {a_0} + {a_1}{T^1} + {a_2}{T^2},{\kern 1pt} {\kern 1pt} {\kern 1pt} \vartheta (z) = {b_0} + {b_1}{T^1} + {b_2}{T^2},
where T = tanh(z). By substituting the values (41) into equation (40), and by the back substitution, we get the solution
(42)
\begin{array}{*{20}{l}}{{\mu _2}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_{13}}(C_{13}^2 + C_{14}^2)}}(8C_{13}^5{\alpha _1} + 16C_{13}^3C_{14}^2{\alpha _1} + 8{C_{13}}C_{14}^4{\alpha _1} + C_{13}^3{\alpha _3} - C_{13}^3{C_{15}}{\alpha _1}}\\{}&{ + {C_{13}}C_{14}^2{\alpha _5} - C_{14}^2{C_{15}}{\alpha _1}) + (2C_{13}^2 + 2C_{14}^2)\mathop {\tanh }\nolimits^2 ({C_{12}} + {C_{13}}x + {C_{14}}y + {C_{15}}t),}\\{{\nu _2}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_{13}}(C_{13}^2{\alpha _3} + C_{14}^2{\alpha _5})}}(8C_{13}^5\alpha _3^2 + 16C_{13}^3C_{14}^2{\alpha _3}{\alpha _5} + 8{C_{13}}C_{14}^4\alpha _5^2}\\{}&{ - C_{13}^3{\alpha _3}{\alpha _4} + C_{13}^3{\alpha _1}{\alpha _2} - {C_{13}}C_{14}^2{\alpha _5}{\alpha _4} + C_{14}^2{C_{13}}{\alpha _1}{\alpha _2} - C_{13}^2{C_{15}}{\alpha _3} - C_{14}^2{C_{15}}{\alpha _5})}\\{}&{ + \frac{{(2C_{13}^2{\alpha _3} + 2C_{14}^2{\alpha _5})}}{{{\alpha _1}}}\mathop {\tanh }\nolimits^2 ({C_{12}} + {C_{13}}x + {C_{14}}y + {C_{15}}t),}\\{}&{}\end{array}
where Ci(i = 1,2,⋯,15) are constants.
We can furnish the solution of (40) by the coth ansatz
(43)
\theta (z) = {a_0} + {a_1}{T^1} + {a_2}{T^2},{\kern 1pt} {\kern 1pt} {\kern 1pt} \vartheta (z) = {b_0} + {b_1}{T^1} + {b_2}{T^2},
where T = coth(z). By substituting the values (43) into equation (40), and by the back substitution, we get the solution as
(44)
\begin{array}{*{20}{l}}{{\mu _3}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}C_5^2(C_5^2 + C_6^2)}}(8C_5^5{\alpha _1} + 16C_5^3C_6^2{\alpha _1} + 8{C_5}C_6^4{\alpha _1} + C_5^3{\alpha _3} - C_5^2{C_8}{\alpha _1}}\\{}&{ + {C_5}C_6^2{\alpha _5} - C_6^2{C_8}{\alpha _1}) + (2C_5^2 + 2C_6^2)\mathop {\coth }\nolimits^2 ({C_1} + {C_5}x + {C_6}y + {C_8}t),}\\{{\nu _3}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_5}(C_5^2{\alpha _3} + C_6^2{\alpha _5})}}(8C_5^5\alpha _3^2 + 16C_5^3C_6^2{\alpha _3}{\alpha _5} + 8{C_5}C_6^4\alpha _5^2 - C_5^3{\alpha _3}{\alpha _4}}\\{}&{ + C_5^3{\alpha _1}{\alpha _2} - {C_5}C_6^2{\alpha _5}{\alpha _4} + C_6^2{C_5}{\alpha _1}{\alpha _2} - C_5^2{C_8}{\alpha _3} - C_6^2{C_8}{\alpha _5})}\\{}&{ + \frac{{(2C_5^2{\alpha _3} + 2C_6^2{\alpha _5})}}{{{\alpha _1}}}\mathop {\coth }\nolimits^2 ({C_1} + {C_5}x + {C_6}y + {C_8}t),}\\{}&{}\end{array}
where Ci(i = 1,2,⋯,8) are constants.
3.3Reduction by 〈ℳ4,ℳ2〉 = 〈Q1,Q3〉
First, consider the vector field
{Q_1} = \frac{\partial }{{\partial t}}
. We get the similarity transformations μ = f (r,s),v = g(r,s), where r = x,s = y. Using these transformations, we obtain the reduced system given by,
(45)
\begin{array}{*{20}{r}}{{\alpha _1}{g_{rrr}} + {\alpha _2}{g_{rss}} + ({\alpha _3} - 6{\alpha _4}g){g_r} - {\alpha _5}{f_r} = 0,}\\{ - 6f{f_r} + {f_{rrr}} + {f_{rss}} - {g_r} = 0.}\end{array}
Now, take
{Q_3} = \frac{\partial }{{\partial y}}
. Q2 +β Q3 in new variables can be written as
{\tilde Q_3} = \frac{\partial }{{\partial s}}
. The similarity variables are written as, f = θ (z),g = ϑ (z) where z = r. The reduced ODE system obtained by using the above transformations is given by,
(46)
\begin{array}{*{20}{r}}{{\alpha _1}\vartheta ''' + ({\alpha _3} - 6{\alpha _4}\vartheta )\vartheta ' - {\alpha _5}\theta ' = 0,}\\{\theta ''' - 6\theta \theta ' - \vartheta ' = 0.}\end{array}
We can also find the solution of (46) by the tanh− coth ansatz [40]
(47)
\theta (z) = \sum\limits_{\varsigma = 0}^2 {a_\varsigma }{{\rm{T}}^\varsigma } + \sum\limits_{\varsigma = 1}^2 {a_\varsigma }{{\rm{T}}^{ - \varsigma }},
(48)
\vartheta (z) = \sum\limits_{\varsigma = 0}^2 {b_\varsigma }{{\rm{T}}^\varsigma } + \sum\limits_{\varsigma = 1}^2 {b_\varsigma }{{\rm{T}}^{ - \varsigma }},
where T = tanh(z). By substituting the values into equation (46), and by the back substitution, we get two sets of solutions for (1)
(49)
\begin{array}{*{20}{l}}{{\mu _4}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_2}(C_2^2 + C_3^2)}}(8C_2^5{\alpha _1} + 16C_2^3C_3^2{\alpha _1} + 8{C_2}C_3^4{\alpha _1} + C_2^3{\alpha _3} - C_2^2{C_5}{\alpha _1}}\\{}&{ + {C_2}C_3^2{\alpha _5} - C_3^2{C_5}{\alpha _1}) + (2C_2^2 + 2C_3^2)\mathop {\tanh }\nolimits^2 ({C_1} + {C_2}x + {C_3}y + {C_5}t),}\\{{\nu _4}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_2}(C_2^2{\alpha _3} + C_3^2{\alpha _5})}}(8C_2^5\alpha _3^2 + 16C_2^3C_3^2{\alpha _3}{\alpha _5} + 8{C_2}C_3^4\alpha _5^2 - C_2^3{\alpha _3}{\alpha _4}}\\{}&{ + C_2^3{\alpha _1}{\alpha _2} - {C_2}C_3^2{\alpha _5}{\alpha _4} + C_3^2{C_2}{\alpha _1}{\alpha _2} - C_2^2{C_5}{\alpha _3} - C_3^2{C_5}{\alpha _5})}\\{}&{ + \frac{{(2C_2^2{\alpha _3} + 2C_3^2{\alpha _5})}}{{{\alpha _1}}}\mathop {\tanh }\nolimits^2 ({C_1} + {C_2}x + {C_3}y + {C_5}t),}\\{}&{}\end{array}
(50)
\begin{array}{*{20}{l}}{{\mu _5}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_2}(C_2^2 + C_3^2)}}(8C_2^5{\alpha _1} + 16C_2^3C_3^2{\alpha _1} + 8{C_2}C_3^4{\alpha _1} + C_2^3{\alpha _3} - C_2^2{C_5}{\alpha _1}}\\{}&{ + {C_2}C_3^2{\alpha _5} - C_3^2{C_5}{\alpha _1}) + 2(C_2^2 + C_3^2)\mathop {\coth }\nolimits^2 ({C_1} + {C_2}x + {C_3}y + {C_5}t),}\\{{\nu _5}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_2}(C_2^2{\alpha _3} + C_3^2{\alpha _5})}}(8C_2^5\alpha _3^2 + 16C_2^3C_3^2{\alpha _3}{\alpha _5} + 8{C_2}C_3^4\alpha _5^2 - C_2^3{\alpha _3}{\alpha _4}}\\{}&{ + C_2^3{\alpha _1}{\alpha _2} - {C_2}C_3^2{\alpha _5}{\alpha _4} + C_3^2{C_2}{\alpha _1}{\alpha _2} - C_2^2{C_5}{\alpha _3} - C_3^2{C_5}{\alpha _5})}\\{}&{ + \frac{{(2C_2^2{\alpha _3} + 2C_3^2{\alpha _5})}}{{{\alpha _1}}}\mathop {\coth }\nolimits^2 ({C_1} + {C_2}x + {C_3}y + {C_5}t).}\\{}&{}\end{array}
We can also find the solution of (46) by the JacobiNS ansatz
(51)
\theta (z) = \vartheta (z) = {\rm{JacobiNS}}.
By substituting the values (51) in the equation (46) and then by back substituting, we have the solution for (1)
(52)
\begin{array}{*{20}{l}}{{\mu _6}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_6}(C_6^2 + C_8^2)}}(4C_1^2C_6^5{\alpha _1} + 8C_1^2C_6^3C_8^2{\alpha _1} + 4C_1^2{C_6}C_8^4{\alpha _1}}\\{}&{ + 4C_6^5{\alpha _1} + 8C_6^3C_8^2{\alpha _1} + 4{C_6}C_8^4{\alpha _1} + C_6^3{\alpha _3} - C_6^3C_9^4{\alpha _1} + {C_6}C_8^2{\alpha _5} - {C_9}C_8^2{\alpha _1})}\\{}&{ + 2(C_6^2 + C_8^2){\rm{JacobiN}}{{\rm{S}}^2}({C_1},{C_5} + {C_6}x + {C_8}y + {C_9}t),}\\{{\nu _6}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_6}(C_6^2{\alpha _3} + C_8^2{\alpha _5})}}(4C_1^2C_6^5\alpha _3^2 + 8C_1^2C_6^3C_8^2{\alpha _3}{\alpha _5} + 4C_1^2{C_6}C_8^4\alpha _5^2}\\{}&{ + 4C_6^5\alpha _3^2 + 8C_6^3C_8^2{\alpha _3}{\alpha _5} + 4{C_6}C_8^4\alpha _5^2 - C_6^3{\alpha _3}{\alpha _4} - C_6^3{\alpha _1}{\alpha _2} - {C_6}C_8^2{\alpha _5}{\alpha _4}}\\{}&{ + {C_6}C_8^2{\alpha _2}{\alpha _1} - {C_9}C_6^2{\alpha _3} - {C_9}C_8^2{\alpha _5})}\\{}&{ + 2\frac{{(C_6^2{\alpha _3} + C_8^2{\alpha _5})}}{{{\alpha _1}}}{\rm{JacobiN}}{{\rm{S}}^2}({C_1},{C_5} + {C_6}x + {C_8}y + {C_9}t).}\end{array}
We can also find the solution of (46) by the JacobiSN ansatz
(53)
\theta (z) = \vartheta (z) = {\rm{JacobiSN}}.
By substituting the values (53) in the equation (46) and then by back substituting, we have the solution for (1)
(54)
\begin{array}{*{20}{l}}{{\mu _7}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_6}(C_6^2 + C_8^2)}}(4C_1^2C_6^5{\alpha _1} + 8C_1^2C_6^3C_8^2{\alpha _1} + 4C_1^2{C_6}C_8^4{\alpha _1} + 4C_6^5{\alpha _1} + 8C_6^3C_8^2{\alpha _1}}\\{}&{ + 4{C_6}C_8^4{\alpha _1} + C_6^3{\alpha _3} - C_6^3C_9^4{\alpha _1} + {C_6}C_8^2{\alpha _5} - {C_9}C_8^2{\alpha _1}) + 2(C_1^2C_6^2}\\{}&{ + C_1^2C_8^2){\rm{JacobiS}}{{\rm{N}}^2}({C_1},{C_5} + {C_6}x + {C_8}y + {C_9}t),}\\{{\nu _7}(x,y,t)}&{ = \frac{{ - 1}}{{6{\alpha _1}{C_6}(C_6^2{\alpha _3} + C_8^2{\alpha _5})}}(4C_1^2C_6^5\alpha _3^2 + 8C_1^2C_6^3C_8^2{\alpha _3}{\alpha _5} + 4C_1^2{C_6}C_8^4\alpha _5^2}\\{}&{ + 4C_6^5\alpha _3^2 + 8C_6^3C_8^2{\alpha _3}{\alpha _5} + 4{C_6}C_8^4\alpha _5^2 - C_6^3{\alpha _3}{\alpha _4} + C_6^3{\alpha _2}{\alpha _1} - {C_6}C_8^2{\alpha _5}{\alpha _4}}\\{}&{ + {C_6}C_8^2{\alpha _2}{\alpha _1} - {C_9}C_6^2{\alpha _3} - {C_9}C_8^2{\alpha _5}) + 2\frac{{(C_6^2{\alpha _3} + C_8^2{\alpha _5})}}{{{\alpha _1}}}{\rm{JacobiS}}{{\rm{N}}^2}({C_1}}\\{}&{,{C_5} + {C_6}x + {C_8}y + {C_9}t).}\end{array}
Next we furnish the solution of (46) by the WeierstrassP ansatz
(55)
\theta (z) = \vartheta (z) = WeierstrassP.
By substituting the values (55) in the equation (46) and then by back substituting, we have the solution for (1)
(56)
\begin{array}{*{20}{l}}{{\mu _8}(x,y,t)}&{ = - \frac{{ - {C_{10}}C_8^2{\alpha _1} - {C_{10}}C_9^2{\alpha _1} + C_8^3{\alpha _3} + {C_8}C_9^2{\alpha _5}}}{{6{\alpha _1}{C_8}(C_8^2 + C_9^2)}} + 2(C_8^2}\\{}&{ + C_9^2){\rm{WeierstrassP}}({C_1},{C_6} + {C_8}x + {C_9}y + {C_{10}}t),}\\{{\nu _8}(x,y,t)}&{ = \frac{{C_8^3({\alpha _3}{\alpha _4} - {\alpha _1}{\alpha _2}) + {C_8}C_9^2({\alpha _5}{\alpha _4} - {\alpha _1}{\alpha _2}) + {C_{10}}C_8^2{\alpha _3} + C_9^2{C_{10}}{\alpha _5}}}{{6{\alpha _1}{C_8}(C_8^2{\alpha _3} + C_9^2{\alpha _5})}}}\\{}&{ + \frac{{2(C_8^2{\alpha _3} + C_9^2{\alpha _5})}}{{{\alpha _1}}}{\rm{WeierstrassP}}({C_1},{C_6} + {C_8}x + {C_9}y + {C_{10}}t),}\end{array}
where Ci(i = 1,2,⋯,15) are constants.
3.4Reduction by 〈ℳ1,ℳ5〉 = 〈Q2,Q1 +β Q3〉
First, consider the vector field
{Q_2} = \frac{\partial }{{\partial x}}
. We get the similarity transformations μ = f (r,s),v = g(r,s), where r = t,s = y. Using these transformations, we obtain the reduced system given by,
(57)
\begin{array}{*{20}{l}}{{f_r} = 0,}\\{{g_r} = 0.}\end{array}
Now, take
{Q_1} + \beta {Q_3} = \frac{\partial }{{\partial t}} + \beta \frac{\partial }{{\partial y}}
. Q1 + β Q3 in new variables can be written as
{\tilde Q_1} + \beta {\tilde Q_3} = \frac{\partial }{{\partial r}} + \beta \frac{\partial }{{\partial s}}
. The similarity variables are written as, f = θ (z),g = ϑ (z) where z = β r − s. The reduced ODE system obtained by using the above transformations is given by,
(58)
\begin{array}{*{20}{l}}{\theta ' = 0,}\\{\vartheta ' = 0,}\end{array}
this implies,
(59)
\begin{array}{*{20}{l}}{\theta = {c_1},}\\{\vartheta = {c_2}.}\end{array}
So, we get
(60)
\begin{array}{*{20}{l}}{f = {c_1},}\\{g = {c_2}.}\end{array}
Hence, the invariant solution of equation (1) in orginal variables becomes
(61)
\begin{array}{*{20}{l}}{{\mu _9}(x,y,t) = {c_1},}\\{{\nu _9}(x,y,t) = {c_2}.}\end{array}
3.5Reduction by 〈ℳ2,ℳ6〉 = 〈Q3,Q4〉
First, consider the vector field
{Q_4} = t\frac{\partial }{{\partial x}} - \frac{1}{6}\frac{\partial }{{\partial \mu }} - \frac{1}{{6{\alpha _4}}}\frac{\partial }{{\partial v}}
. We get the similarity transformations
\mu = - \frac{x}{{6t}} + f(r,s),v = - \frac{x}{{6{\alpha _4}t}} + g(r,s)
, where r = t,s = y. Using these transformations, we obtain the reduced system given by,
(62)
\begin{array}{*{20}{r}}{6{\alpha _4}r{f_r} + 6{\alpha _4}f + 1 = 0,}\\{6{\alpha _4}r{g_r} + 6{\alpha _4}g + {\alpha _4}{\alpha _5} - {\alpha _3} = 0.}\end{array}
Now, take
{Q_3} = \frac{\partial }{{\partial y}}
. Q3 in new variables can be written as
{\tilde Q_3} = \frac{\partial }{{\partial s}}
. The similarity variables are written as, f = θ (z),g = ϑ (z) where z = r. The reduced ODE system obtained by using above transformations is given by,
(63)
\begin{array}{*{20}{r}}{6{\alpha _4}z\theta ' + 6{\alpha _4}\theta + 1 = 0,}\\{6{\alpha _4}z\vartheta ' + 6{\alpha _4}\vartheta + {\alpha _4}{\alpha _5} - {\alpha _3} = 0,}\end{array}
this implies,
(64)
\begin{array}{*{20}{r}}{\theta = - \frac{1}{{6{\alpha _4}}} + \frac{{{c_1}}}{z},}\\{\vartheta = - \frac{{{\alpha _5}}}{6} + \frac{{{\alpha _3}}}{{6{\alpha _4}}} + \frac{{{c_2}}}{z}.}\end{array}
So, we get
(65)
\begin{array}{*{20}{r}}{f = - \frac{1}{{6{\alpha _4}}} + \frac{{{c_1}}}{r},}\\{g = - \frac{{{\alpha _5}}}{6} + \frac{{{\alpha _3}}}{{6{\alpha _4}}} + \frac{{{c_2}}}{r}.}\end{array}
Hence, the invariant solution of equation (1) in original variables becomes:
(66)
\begin{array}{*{20}{r}}{{\mu _{10}}(x,y,t) = \frac{{( - x + 6{c_1}){\alpha _4} - t}}{{6{\alpha _4}t}},}\\{{\nu _{10}}(x,y,t) = \frac{{ - x + {\alpha _4}t + {\alpha _4}(6{c_2} - {\alpha _5}t)}}{{6{\alpha _4}t}},}\end{array}
where ci(i = 1,2,⋯,4) are constants.
4Conservation laws for the CZK
(1)
Regarding [41], Ibragimov introduced a groundbreaking theorem that deals with conserved vectors in the context of differential equations. This theorem is particularly relevant in systems of differential equations where the number of equations matches the number of dependent variables. What sets this theorem apart is its remarkable independence from the presence of a classical Lagrangian. Ibragimov’s approach establishes a vital link between each infinitesimal generator and a conserved vector. This concept is expressed through a specially crafted adjoint equation designed for nonlinear differential equations. Looking ahead, we will provide a comprehensive overview of this theorem.
Let us examine a differential system comprising k differential equations.
(67)
{\mathcal{P}_\gamma }(x,\mu ,{\mu _{(1)}}, \cdots ,{\mu _{(k)}}) = 0,\quad \gamma = 1,2, \cdots ,k.
In this context, we have a differential system with n independent variables denoted as x = (x1,x2,⋯,xn) and a system consisting of k dependent variables denoted as μ = (μ (1),⋯,μ (k)). The variational derivative is defined as follows
(68)
\frac{\delta }{{\delta \mu }} = \frac{\partial }{{\partial \mu }} + \sum\limits_{i = 1}^\infty {( - 1)^s}{\mathfrak{D}_{{i_1}}} \cdots {\mathfrak{D}_{{i_s}}}\frac{\partial }{{\partial {\mu _{{i_1} \cdots {i_s}}}}} \cdot
This operator, known as the Euler-Lagrange operator, is represented by the term 𝔇i, which takes the following form:
(69)
{\mathfrak{D}_i} = \frac{\partial }{{\partial {x_i}}} + {\mu _i}\frac{\partial }{{\partial \mu }} + {\mu _{ij}}\frac{\partial }{{\partial {\mu _j}}} + \cdots .
Theorem 2
Any form of symmetry, (whether it is a Lie point symmetry, Lie-Bäcklund, or nonlocal symmetry), is denoted as
(70)
Q = {\varphi ^i}(x,\mu ,{\mu _{(1)}}, \cdots )\frac{\partial }{{\partial {x^i}}} + {\rho ^\gamma }(x,\mu ,{\mu _{(1)}}, \cdots )\frac{\partial }{{\partial {\mu ^\gamma }}},
is inherited by the adjoint system. Particularly, the operator
(71)
Q = {\varphi ^i}\frac{\partial }{{\partial {x^i}}} + {\rho ^\gamma }\frac{\partial }{{\partial \mu }} + \rho _*^\gamma \frac{\partial }{{\partial \nu }},
accompanied by a appropriately chosen coefficient
\rho _*^\gamma = \rho _*^\gamma (x,\mu ,\nu , \cdots )
, is incorporated into the system, which includes equation (67) and its corresponding adjoint equation. This expression can be stated as follows
(72)
\mathcal{P}_\gamma ^ \star (x,\mu ,\nu ,{\mu _{(1)}},{\nu _{(1)}}, \cdots {\mu _{(k)}},{\nu _{(m)}}) \equiv \frac{{\delta ({v^i}{\mathcal{P}_i})}}{{\delta {\mu ^\gamma }}} = 0,\ \ \ \gamma = 1,2, \cdots ,k.
Furthermore, when examining the system formed by equations (67) and (72), it displays a conservation law represented as 𝔇i (𝒲i) = 0, where
(73)
\begin{array}{*{20}{l}}{{\mathcal{W}^i} = }&{{\varphi ^i}\mathcal{L} + {\mathcal{H}^\gamma }[\frac{{\partial \mathcal{L}}}{{\partial {\mu _i}}} - {\mathfrak{D}_j}(\frac{{\partial \mathcal{L}}}{{\partial {\mu _{ij}}}}) + {\mathfrak{D}_j}{\mathfrak{D}_k}(\frac{{\partial \mathcal{L}}}{{\partial {\mu _{ijk}}}}) + \cdots ]}\\{}&{ + {\mathfrak{D}_j}({\mathcal{H}^\gamma })[\frac{{\partial \mathcal{L}}}{{\partial {\mu _{ij}}}} - {\mathfrak{D}_k}(\frac{{\partial \mathcal{L}}}{{\partial {\mu _{ijk}}}}) + \cdots ] + {\mathfrak{D}_j}{\mathfrak{D}_k}({\mathcal{H}^\gamma })[\frac{{\partial \mathcal{L}}}{{\partial {\mu _{ijk}}}} + \cdots ].}\end{array}
In this context, function ℋγ is associated with the existence of conserved vectors and is commonly known as the Lie characteristic function
(74)
{\mathcal{H}^\gamma } = {\varphi ^\gamma } - {\varphi ^i}{\mu ^\gamma }.
Now, by applying the aforementioned theorem, we will derive the nonlocal conservation law for the system (1).
Theorem 3
The adjoint equations for the system of equations (1) are provided as follows
(75)
\begin{array}{*{20}{l}}{\mathcal{P}_1^ \star }&{ = \frac{{\delta {\mathcal{P}_1}}}{{\delta \mu }} = {w_t} - 6{w_x}\mu - {\alpha _5}{z_x} + {w_{xxx}} + {w_{yyx}} = 0,}\\{\mathcal{P}_2^ \star }&{ = \frac{{\delta {\mathcal{P}_2}}}{{\delta \nu }} = - 6{\alpha _4}\nu z - {z_t} + {w_x} - {\alpha _3}{z_x} + 6{\alpha _4}{z_x}\nu + 6{\alpha _4}{\nu _x}z - {\alpha _1}{z_{xxx}} - {\alpha _2}{z_{yyx}} = 0,}\end{array}
where the formal Lagrangian is given by
(76)
\mathcal{L} = w({\mu _t} + {\mu _{xxx}} + {\mu _{yyx}} - 6\mu {\mu _x} - {\nu _x}) + z({\nu _t} + {\alpha _1}{\nu _{xxx}} + {\alpha _2}{\nu _{yyx}} + {\alpha _3}{\nu _x} - 6{\alpha _4}\nu {\nu _x} - {\alpha _5}{\mu _x}),
and μ = μ (x,y,t), ν = ν (x,y,t) are functions.
Following the Ibragimov theorem, each symmetry generator corresponds to a conserved vector. Therefore, we can now proceed with the calculation of the conserved vectors using the formulation provided in Theorem 2.
(I) When we consider
{Q_1} = \frac{\partial }{{\partial t}}
, it becomes evident that both the ℋ1 = −μt and ℋ2 = −μt are nonzero, indicating the presence of conserved quantities. To derive the associated conserved vector, we can follow as
(77)
\begin{array}{*{20}{l}}{\mathcal{W}_1^t = }&{w({\mu _{xxx}} + {\mu _{yyx}} - 6\mu {\mu _x} - {\nu _x}) + z({\nu _t} + {\alpha _1}{\nu _{xxx}} + {\alpha _2}{\nu _{yyx}} + {\alpha _3}{\nu _x} - 6{\alpha _4}\nu {\nu _x} - {\alpha _5}{\mu _x}) - {\mu _t}z,}\\{}&{}\\{\mathcal{W}_1^x = }&{{\mu _t}(6w\mu + {\alpha _5}z + w - {\alpha _3}z + {\alpha _4}\nu z - {w_{yy}} - {\alpha _2}z{z_{yy}}) - {\mu _t}{w_{xx}} - {\alpha _1}{\mu _t}{z_{xx}} - {\mu _{xt}}{w_x}}\\{}&{ - {\alpha _1}{\mu _{xt}}z - {\mu _{xt}}w + {\alpha _1}{\mu _{xxt}}z - {\mu _{yt}}{w_y} - {\mu _{yt}}{z_y} - {\mu _{yyt}}w - {\alpha _2}{\mu _{yyt}}z,}\\{}&{}\\{\mathcal{W}_1^y = }&{ - {\mu _t}({w_{yy}} + {\alpha _2}{z_{yy}}) - {\mu _{xt}}{w_x} - {\alpha _2}{\mu _{xt}}{z_x} - {\mu _{yyt}}w - {\alpha _2}{\mu _{yyt}}z.}\\{}&{}\end{array}
(II) When we consider
{Q_2} = \frac{\partial }{{\partial x}}
, it becomes evident that both the ℋ1 = −μx and ℋ2 = −μx are nonzero, indicating the presence of conserved quantities. To derive the associated conserved vector, we can follow as
(78)
\begin{array}{*{20}{l}}{\mathcal{W}_2^t = }&{ - {\mu _x}(w + z),}\\{}&{}\\{\mathcal{W}_2^x = }&{w({\mu _t} + {\mu _{xxx}} - {\nu _x}) + z({\nu _t} + {\alpha _1}{\nu _{xxx}} + {\alpha _2}{\nu _{yyx}} + {\alpha _3}{\nu _x} - 6{\alpha _4}\nu {\nu _x} - {\alpha _5}{\mu _x})}\\{}&{ + {\mu _x}({\alpha _5}z + w - {\alpha _3}z + 6{\alpha _4}\nu z) - {\mu _x}{w_{xx}} - {\alpha _1}{z_{xx}}{\mu _x} - {\mu _{xx}}{w_x} - {\alpha _1}{\mu _{xx}}z}\\{}&{ - {\mu _{xxt}}w - {\alpha _1}{\mu _{xxt}}z - {\mu _x}{w_{yy}} - {\alpha _2}{\mu _x}{z_{yy}} + {\mu _{yx}}{w_y} + {\mu _{yx}}{z_y} - {\mu _{yyx}}w - {\alpha _2}{\mu _{yyx}}z,}\\{}&{}\\{\mathcal{W}_2^y = }&{ - {\mu _x}({w_{yy}} + {\alpha _2}{z_{yy}}) + {\mu _{xx}}{w_x} + {\alpha _2}{\mu _{xx}}{z_x} - {\mu _{yyx}}w - {\alpha _2}{\mu _{yyx}}z.}\\{}&{}\end{array}
(III) When we consider
{Q_3} = \frac{\partial }{{\partial y}}
, it becomes evident that both the ℋ1 = −μy and ℋ2 = −μy are nonzero, indicating the presence of conserved quantities. To derive the associated conserved vector, we can follow as
(79)
\begin{array}{*{20}{l}}{\mathcal{W}_3^t = }&{ - {\mu _y}(w + z),}\\{}&{}\\{\mathcal{W}_3^x = }&{{\mu _y}(6w\mu + {\alpha _5}z + w - {\alpha _3}z + 6{\alpha _4}\nu z - {w_{xx}} - {\alpha _1}{\mu _y}{z_{xx}} - {w_{yy}} - {\alpha _2}{z_{yy}}) - {\alpha _1}{\mu _{yz}}z}\\{}&{ - {\mu _{yy}}{w_x} + {\mu _{yxx}}w - {\alpha _1}{\mu _{yxx}}z - {\mu _{yy}}{w_y} - {\mu _{yy}}{z_y} - {\mu _{yy}}w - {\alpha _2}{\mu _{yy}}z,}\\{}&{}\\{\mathcal{W}_3^y = }&{w({\mu _t} + {\mu _{xxx}} + {\mu _{yyx}} - 6\mu {\mu _x} - {\nu _x}) + z({\nu _t} + {\alpha _1}{\nu _{xxx}} + {\alpha _2}{\nu _{yyx}} + {\alpha _3}{\nu _x} - 6{\alpha _4}\nu {\nu _x}}\\{}&{ - {\alpha _5}{\mu _x}) - {\mu _y}{w_{yy}} - {\alpha _2}{\mu _y}{z_{yy}} + {\mu _{yx}}{w_x} + {\alpha _2}{\mu _{yx}}{z_x} - {\mu _{yyy}}w - {\alpha _2}{\mu _{yyy}}z.}\end{array}
(IV) When we consider
{Q_4} = t\frac{\partial }{{\partial x}} - \frac{1}{6}\frac{\partial }{{\partial \mu }} - \frac{1}{{6{\alpha _4}}}\frac{\partial }{{\partial \nu }}
, it becomes evident that both the
{\mathcal{H}^1} = - \frac{1}{6} - t{\mu _x}
and
{\mathcal{H}^2} = - \frac{1}{{6{\alpha _4}}} - t{\mu _x}
are nonzero, indicating the presence of conserved quantities. To derive the associated conserved vector, we can follow as
(80)
\begin{array}{*{20}{l}}{\mathcal{W}_4^t = }&{ - w(\frac{1}{6} + t{\mu _x}) - z(\frac{1}{{6{\alpha _4}}} + t{\mu _x}),}\\{}&{}\\{\mathcal{W}_4^x = }&{t\mathcal{L} + (\frac{1}{6} + t{\mu _x})(6w\mu + {\alpha _5}z) - (\frac{1}{{6{\alpha _4}}} + t{\mu _x})(w - {\alpha _3}z + 6{\alpha _4}\nu z) - (\frac{1}{6} + t{\mu _x}){w_{xx}}}\\{}&{ - {\alpha _1}(\frac{1}{{6{\alpha _4}}} + t{\mu _x}){z_{xx}} + (\frac{1}{6} + t{\mu _x}){w_x} + {\alpha _1}(\frac{1}{{6{\alpha _4}}} + t{\mu _x})z - (\frac{1}{6} + t{\mu _x})w}\\{}&{ - {\alpha _1}(\frac{1}{{6{\alpha _4}}} + t{\mu _x})z - (\frac{1}{6} + t{\mu _x}){w_{yy}} - {\alpha _2}(\frac{1}{{6{\alpha _4}}} + t{\mu _x}){z_{yy}} + (\frac{1}{6} + t{\mu _{yx}}){w_y} + (\frac{1}{{6{\alpha _4}}} + t{\mu _{yx}}){z_y}}\\{}&{ - (\frac{1}{6} + t{\mu _{yyx}})w - {\alpha _2}(\frac{1}{{6{\alpha _4}}} + t{\mu _{yyx}})z,}\\{}&{}\\{\mathcal{W}_4^y = }&{ - (\frac{1}{6} + t{\mu _x}){w_{yy}} - {\alpha _2}(\frac{1}{{6{\alpha _2}}} + t{\mu _x}){z_{yy}} + t{w_x}{\mu _{xx}} + {\alpha _2}t{\mu _{xx}}{z_x} - t{\mu _{yyx}}w - {\alpha _2}tz{\mu _{yyx}}.}\end{array}