1. Introduction
Recently, there has been a lot of interest in the systematic study of problems involving non-local operators due to their frequency in practical real-world applications, such as finance, optimization, soft thin films, stratified materials, and phase transitions. We refer the reader to see [32]. The elliptic theory for linear and quasilinear nonlocal operators has seen extensive research over the past few decades, particularly in the works of Caffarelli and collaborators [4, 5, 14]. Additionally, research on nonlocal nonlinear problems has been extensively explored in [30], we also refer to [9, 10, 11, 15, 22, 24, 25, 26, 31] on related existence results for the problems of elliptic and parabolic type involving non-local fractional Laplacian (p-Laplacian) operators.
In this paper, suppose that Ω is a bounded open domain of ℝn and T is a real positive number. We deal with the following initial boundary value problem:
where 0 < s < 1 and 2 < p are real numbers, u: Ω × (0, T) → ℝm, m ∈ {0, 1, 2, . . .} is a vector-valued function and the function f satisfies the following hypothesis:(H1) f : Ω × (0, T) × ℝm → ℝm is a Carathéodory function satisfying
for all (x, t, r) ∈ Ω × (0, T) × ℝm, where α0, α1 are positive constants, and .
The fractional p-Laplacian operator is defined as follows:
where P.V stands for “in the principal value sense” and is a frequently used abbreviation. For more information on this operator, see [13].Concerning the fractional Laplacian (p = 2), a famous model for anomalous diffusion is the following equation: , which comes asymptotically from basic random walk models (see [33, 34]). Also in [17], de Pablo et al. proposed the nonlinear anomalous diffusion equation , the fractional porous medium equation with 0 < s < 1 and m > 0. We also refer to [34] for more details on this type of equation.
On the other hand, in the case p ≠ 2 and f = 0, Vázquez in [35] proved the existence and uniqueness of strong nonnegative solutions for (1.1). If u0 ∈ L2(Ω), the existence results of energy solution were studied in [29].
When it comes to the problem (1.1), the existence results are treated in several works, for example, the different issues of the existence and the regularity of energy-weak solutions to the problem same to (1.1) were investigated by Giacomoni et al. in [21]. In [1], the authors have studied the problem (1.1) with f depending only on x and t and proved the existence results with suitable regularity if (f, u0) ∈ L1 (ΩT) × L1(Ω) and has a nonnegative entropy solution if f0, u0 are nonnegative. The same author in [2] proved the asymptotic behavior result of entropy solutions when the right-hand side does not depend on time.
The idea of this work, motivated by all of the results above, is to study the existence of weak solutions to the problem (1.1) by using the Galerkin method combined with the theory of Young measures. To the best of our knowledge, the parabolic problem (1.1) has never been studied by the theory of Young measure. We suggest to the readers to consult [6, 7, 19] which treat some elliptic and parabolic systems by such a theory. In [8], the authors proved the existence of weak solutions to the elliptic case of (1.1) employing the Young measures theory and the Galerkin method.
This article is organized into four sections. In Section 2 we give some background information on fractional Sobolev spaces and a review of the Young measures theory. Later, under some assumptions, we obtain the existence of weak solutions using the Galerkin approximation and the Young measures. The final part is devoted to illustrating the feasibility of the hypotheses with an example.
2. Preliminaries and notations
In this section, we first recall some necessary results which will be used in the next section. Let 1 < p < ∞, s ∈ (0, 1), we define the fractional critical exponent by:
Let Ω ⊂ ℝn be an open set, QΩ = (ℝn × ℝn) \(𝒞Ω × 𝒞Ω), Qτ = Ω × (0, τ) for all τ ∈ (0, T ] and 𝒞Ω = ℝn\Ω. It is clear that Ω × Ω is strictly contained in QΩ. W is a linear space of Lebesgue measurable functions from ℝn to ℝm such that the restriction to Ω of any function u in W belongs to Lp(Ω; ℝm) and The space W is equipped with the norm Let us consider the closed linear subspace In W0, we may also use the norm It is known that (W0, ∥ · ∥W0) is a uniformly convex reflexive Banach space (see [36]). The following Poincare’s inequality from [12] will be used below: there exists Cr > 0 such that In the sequel, let and Ci, i = 1, 2, . . . be positive constants that vary from line to line, and are independent of the terms involved in any limit process. We note the following functional space Lp(0, T; W0), which is a separable and reflexive Banach space endowed with the normLemma 2.1. ([20])
The space of infinitely differentiable functions with compact support on Ω is dense in W0.
Lemma 2.2. ([18])
The following embedding W0 ↪ Lr (Ω; ℝm) is compact for all , and continuous for all .
In the following, 𝒞0 (ℝm) stands for the space of continuous functions on ℝm with compact support with regards to the ∥·∥∞-norm. The space of signed Radon measures with finite mass is noted ℳ (ℝm). The corresponding duality is given by
Definition 2.3. ([8])
Let {zj}j≥1 be a bounded sequence in L∞ (Ω; ℝm). Then there exist a subsequence {zk} ⊂ {zj} and a Borel probability measure µx on ℝm for almost every x ∈ Ω, such that for a.e. ρ ∈ 𝒞 (ℝm) we have weakly in L∞(Ω), where for a.e. x ∈ Ω.
Lemma 2.4. ([23])
Let Ω ⊂ ℝn be Lebesgue measurable (not necessarily bounded) and zj from Ω to ℝm, for j ∈ ℕ, be a sequence of Lebesgue measurable functions. Then there exist a subsequence zk and a family {µx}x∈Ω of non-negative Radon measures on ℝm, such that
(i) ∥µx∥ℳ(ℝm) := ∫ℝm dµx(λ) ≤ 1 for almost every x ∈ Ω.
(ii) weakly in L∞(Ω) for all 𝒞0 (ℝm), where .
(iii) If for all M > 0
then ∥µx∥ = 1 for a.e. x ∈ Ω, and for any measurable Ω′ ⊂ Ω we have weakly in L1 (Ω′) for continuous function ρ provided the sequence ρ (zk) is weakly precompact in L1 (Ω′).
3. Local existence of weak solutions
In this section, we define a weak solution to the problem (1.1) and prove the main result (Theorem 3.2 below). We start with the following definition:
Definition 3.1
A function u ∈ Lp(0, T; W0) is called a weak solution of (1.1), if and
holds for all .Assertion 1: Galerkin approximation
Similar to that in [27], we take a sequence , such that , where {wj}j≥1 is an orthonormal basis in L2 (Ω; ℝm) and Uk = span {w1, . . . , wk}.
Lemma 3.3
For the function u0 ∈ W0, there exists a subsequence ξk ∈ Uk such that ξk → u0 in W0 as k → ∞.
Proof
Since u0 ∈ W0, we can find a sequence {vk} in such that vk → u0 in W0. Since , there exists a sequence such that in as i tends to ∞. For , there exists ik ≥ 1 such that . Therefore
Hence in W0 as k tends to ∞. We denote . Since uk ∈ UM≥1 UM, there exists UMk such that uk ∈ UMk, without loss of generality, we assume that UM1 ⊂ UM2 as M1 ≤ M2. We suppose that M1 > 1 and define ξk as follows: Then {ξk} is the desired sequence such that ξk → u0 in W0 as k → ∞.We define the function Rk : [0, T) × ℝk → ℝk where k is fixed:
for ς ∈ ℝk and i = 1, . . . , k. The function R(t, ς) is continuous in t and ς.Now, we shall construct the approximating solutions for (1.1) as follows:
where unknown functions (b(t))j are determined by the following system of ODE: where and Multiplying (3.1) by b(t), we get According to (H1), the following inequalities hold Since , using the interpolation inequality (see [3, Theorem 2.11]) and (2.1), we get where θ ∈ (0, 1) satisfies We observe that and For any ϵ ∈ (0, 1), the Young inequality implies Then, (3.4) is transformed into the following inequality Plugging inequalities (3.3), (3.4) and (3.6) into (3.2), we deduce that By choosing , we get It follows that Denote z(t) = |b(t)|2, then Integrating (3.8) from 0 to t, and using the property we can conclude that For , we obtain that |b(t)| ≤ C(T) ∀t ∈ [0, T ], where Put where B(b(0), 2C(T)) is the ball of center b(0) and radius 2C(T). By [16, Peano theorem], we know that problem (3.1) has a C1 solution on [0, βk]. Let b (βk) be an initial value, then we can repeat the above process and get a C1 solution on [βk, 2βk]. Without loss of generality, we assume that where is the integer part of and is the decimal part of . We can divide [0, T ] into [(i − 1)βk, iβk], i = 1, . . . , N and [Nβk, T ] where , then there exist C1 solution in [(i − 1)βk, iβk], i = 1, . . . , N and in [Nβk, T ]. Therefore, we get a solution bk(t) ∈ C1([0, T ]) defined by As a result, we get the desired Galerkin approximation solution.Assertion 2: A priori estimates
By (3.1), we have
where 1 ≤ i ≤ k and t ∈ [0, T ] (T < T0).Multiplying (3.9) by (b(t))i (resp. by ) and summing with respect to i from 1 to k, we arrive at (integrating with respect to t from 0 to τ (τ ∈ (0, T ]))
According to (3.7), we have
Similar to the estimation of b(t), we have Moreover Hence, we get According to (3.10) and (H1), we get From the fact applied to (3.14), we deduce By using the same technique in (3.5) and using (3.11) to the term in the right-hand side of (3.15), we get Integrating (3.16) with respect to t from 0 to τ (τ ∈ (0, T ]) and using the strong convergence in uk(x, 0) → u0(x) in W0, we get By assumption (H1) and interpolation inequality used in (3.5), we get Plugging (3.18) in (3.17), we arrive at By choosing , we get The Gronwall inequality implies that for each τ ∈ [0, T ]. Therefore We finally get The assumption (H1) implies thatAssertion 3: Passage to the limit
By virtue of (3.12), (3.13), (3.19), and (3.20), we get the existence of a subsequence of (uk) still denoted by (uk) such that
[28, Theorem 5.1] and (3.21) imply that uk → u in Lp(0, T, L2(Ω; ℝm)) and a.e. on QT (for a subsequence), and [28, Lemma 1.3] implies that f(x, t, u) = χ. We can conclude from the continuity in (H1), Using the Vitali Theorem, we get By , we get the existence of a subsequence of (uk) still denoted by (uk) and a function û in L2 (Ω; ℝm) such that uk(x, T) → û in L2 (Ω; ℝm). Then, for any b(t) ∈ C1([0, T ]) and ,Tending k to ∞, we get
Choosing b(T) = 1, b(0) = 0 or b(T) = 0, b(0) = 1, we have û = u(x, T) and u0(x) = u(x, 0).As stated in the introduction, Young measure is the tool we use to prove the existence of a weak solution. To identify the weak limit, we consider the following lemma:
Lemma 3.4
Suppose that (3.12) holds. Then, the Young measure µ(x,y,t) generated by has the following properties:
(a) ∥µ(x,y,t)∥ℳℝm= 1 for a.e. (x, y, t) ∈ QΩ × (0, T), i.e. µ(x,y,t) is a probability measure.
(b) is the weak L1-limit of .
(c) for a.e. (x, y, t) ∈ QΩ × (0, T).
Proof
(a) For simplicity reasons, we consider
We know that for any M > 0, (Ω ∩ BM)2 ⊆ Ω × Ω ⫅̸ QΩ, where BM is the ball centered in 0 with radius M. Let N ∈ ℝ be such that Using (3.12), we get Consequently, there exists C16 ≥ 0 such that where |QN | is the Lebesgue measure of QN. According to (3.23), the sequence (vk) satisfies (2.2). Hence, a Young measure noted by µ(x, y, t) is generated by vk such that ∥µ(x, y, t)∥ℳ(ℝm) = 1 for a.e. (x, y, t) ∈ QΩ × (0, T).(b) By (3.12), there exists a subsequence still denoted by (vk) that converges in Lp (QΩ × (0, T); ℝm). Since Lp (QΩ × (0, T); ℝm) is reflexive, then vk is weakly convergent in L1 (QΩ × (0, T); ℝm). By the third assertion in Lemma 2.4, we replace the function ρ by the identity function, to obtain
(c) According to (3.12), vk is bounded in Lp (QΩ × (0, T); ℝm), then there exists a subsequence such that vk ⇀ v in Lp (QΩ × (0, T); ℝm). Owing to the previous arguments, we get from the uniqueness of limits that
Now, let {vk} be the sequence given in (3.22), i.e.
The weak convergence given in Lemma 3.4 shows that weakly in L1 (QΩ × (0, T); ℝm). Since the space Lp is reflexive and |vk(x, y, t)|p−2vk(x, y, t) is bounded in Lp′(QΩ × (0, T); ℝm), the sequence |vk(x, y, t)|p−2vk(x, y, t) converges in Lp′ (QΩ × (0, T); ℝm). Hence its weak Lp′-limit is also |v(x, y, t)|p−2v(x, y, t). Thus, for any φ ∈ Lp(0, T; W0) we have According to the weak limit in (3.24), we get for every φ ∈ Lp(0, T; W0).From (3.9), for ϕ ∈ C1 (0, T; UM), M ≤ k, we have
For k tending to ∞, it follows from the above results, that for all . Letting M goes to infnity, consequently, (3.25) holds for all .4. An example
We consider the following problem
comparing it with problem (1.1) where f(x, t, u) = a(x, t) |u|q−2u, , and Ft(x, t, u) ⩾ C(−|r|q − 1). If , then by Theorem 3.2, there exists a constant T0 > 0 such tha the problem (1.1) has a weak solutions as T < T0.